For KCl:
We know
In total,
In total,
200 mL of soln, 5 mEq of
Thus, the total mEq in 200 mL is:
Because we have the hydrated salt, whihc dissociates as follows:
Each mole of
so
Knowing we need 0.100 mol of
What is the number of milliosmoles contained in the following solution? - $\mathrm{MgCl_2\cdot6H_2O}$ (MW = 203.3): 3.7 g - $\mathrm{KCl}$ (MW = 74.6): 3.0 g - Water for injections, to 100 mL -
Calculate the number of milliosmoles (mOsm) in the following solution: - 50 mL of 0.067 M $\mathrm{KH_2PO_4}$ (0.908\% w/v) (MW = 136) - 50 mL of 0.067 M $\mathrm{Na_2HPO_4\cdot12H_2O}$ (2.39\% w/v) (MW = 358)